$2yy'+5=y^2 +5x$ with $y(0)=6$
- To solve this, we should use the substitution
With this substitution,
After the substitution from the previous part, we obtain the following linear differential equation in $x, u, u'$
The solution to the original initial value problem is described by the following equation in $x,y$.
I need a step-by-step $u$-substitution but have no idea how to work it out.
I found the answer on wolfram but I have no idea how to solve it.