Prove that for any integer $n$, if $b^2$ divides $n$, then $b$ divides $n$.
Trying to figure out this proof. The proof I'm looking at is written as $n$ = any integer, if $25|n \implies 5|n$. I've been trying to figure this for days and have been running around in circles. Would appreciate a general proof for this.
$n$ = any integer, if $(b^2)|n \implies b|n$.