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Assume that we define edge coloring in this way :
An edge coloring of a graph is an assignment of "colors" to the edges of the graph.
So, now imagine we have a $K_8$ which has edges colored with just 2 colors ( for example, red and blue )
Can we find a $k_4$ which is colored with just 1 color?
Note : In our class , teacher proved this for $k_6$ and $k_3$ . i mean that we have a $k_3$ with just 1 color in a $k_6$ that is colored with 2 colors. now i'm not sure about this one. so, if it's correct , please provide a proof. if it's not, please prove that too .
Thanks in advance.

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  • $\begingroup$ What is the minimum size of a set of edges such that each $K_4$ contains at least one edge in the set? $\endgroup$ – deinst Jan 31 '16 at 17:53
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What you want to prove is that the ramsey number $R(4,4)$ is less than or equal to $8$.

This is false, we know that $R_{4,4}$ is in fact $18$.

Here is a simple counterexample for $K_8$:

enter image description here

To see why it is a counterexample notice if we pick $4$ vertices at least $2$ vertices will be distance $3$ or more apart, so at least one red edge, on the other hand, there will also be two vertices will be distance $1$ or $2$ apart, so at least one blue edge.

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    $\begingroup$ thank you dude :) today was our first Combinatorics class and i'm a newbie at ramsey theory ! but i found it so cool ! $\endgroup$ – Arman Malekzadeh Jan 31 '16 at 18:05
  • $\begingroup$ You're welcome, happy to help. $\endgroup$ – Jorge Fernández Hidalgo Jan 31 '16 at 18:06

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