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What is the method finding the closed form of $\displaystyle\sum_{k=1}^{n}\frac{2k-1}{2^k}$?

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  • $\begingroup$ You can use summation by parts. $\endgroup$ – Arbuja Jan 30 '16 at 17:35
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    $\begingroup$ Don't look for "the" method; look for "a" method. You'll probably never find a math problem for which there is only one method of solving it. $\qquad$ $\endgroup$ – Michael Hardy Jan 30 '16 at 18:25