GRE Algebra answer is wrong GRE study guide has following

A developer has land that has $x$ feet of lake frontage. The land is
  to be subdivided into lots, each of which is to have either 80 feet or
  100 feet of lake frontage. If $(\frac{1}{9}$ of the lots are to have
  80 feet of frontage each and the remaining 40 lots are to have 100
  feet of frontage each, what is the value of x?

Choices


*

*400

*3,200

*3,700

*4,400

*4,760


I calculated x as
$(\frac{8}{9})x = 4000$
$x = 4000(\frac{9}{8})$
$x = 4500$
But the GRE says answer is 4400. Please explain.
 A: Let $n$ be the number of lots, we have $\frac{8}{9}n=40$, or $n=45$. So we see that 40 lots have 100 ft and 5 lots have 80 feet, giving 4400 feet of lake front.
A: $$40 \cdot 100 + 5 \cdot 80 = 4400$$
In this equation, the first factor of each product is the number of lots, and the second factor of each product is the length of the lots. 
If you assign units to your equation, you'll find that they are inconsistent.
Edit - because someone isn't a fan!
Writing $\dfrac{8}{9}x = 4000$ implies that $x$ is $8/9$ of the length, when it's actually $8/9$ of the [number of] lots. 
A: Since the lots are not equal in length 8/9 of the lots will not have 8/9ths of total length. These lots (100 feet) are larger than the remaining lots (80 feet) so they have more than 8/9 of the length.  (Just like if 1% of population are very rich, they have more than 1% of the money because the money isn't distributed evenly.
So $\frac 8 9 x \ne 4000$.
If $n$ is the total number of lots $n*\frac 1 9*80 + 40*100 = n\frac 1 9*80 + n*\frac 8 9 *100 = x$
What is $n$ and what is $x$?
We are told $8/9 n = 40$ so $n = 40*(9/8) = 45$
So $5*80 + 40*100 = x$.
