Determine the number of six digit integers in which no digit may be repeated and the integers are even.
I understand how to do this when we are repeating digits
When repetition is not allowed, the total number of integers is given by
Would it be correct to divide the above by $2$. I basically figured that because the total is even, dividing by $2$ will give me the total number of even integers. But, is there another way to get to the right answer using permutation formulas?