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A dishonest dealer marks his goods $20\%$ above the cost price. He gives a discount of $10\%$ to the customer on the marked price and makes a profit by using a false weight of $900$ gms in place of $1$ kg while buying or selling. Find the percentage profit earned by the shopkeeper.

I do tried this problem but am not quite there,hints are welcome :-)

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The dealer doesn't actually give his customer a discount. He charges 90% of the price for 90% of the product. Thus he still makes a 20% profit over the supplier price. Let $C$ be the supplier price for 1 kg of product. The dealer then gets 1.1kg for the price $C$ or 1kg for $10\over{11}$$C$. He sells this 1kg for $1.2C$. The profit margin is $1.2C$-$10\over{11}$$C$ divided by the dealer price, $10\over{11}$$C$, which I calculate to be 32%.

Here I have assumed the "cost price" is the supplier price, $C$. If you assume the cost price is what the dishonest dealer actually pays his supplier, you will get a different answer still.

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  • $\begingroup$ The dealer uses false weight in both buying and selling,so he buys $1100$ gm and sells $900$ gms. $\endgroup$ – Quixotic Jan 2 '11 at 11:16
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Solution: Let when buying-- 1100 gm at Rs. 1000 when selling-- 900 gm at Rs. 1080 [20% mark up & 10% discount] so, the selling price of 1100 gm =Rs. (1080*1100)/900 =Rs. 1320 Profit%= (320*100)/1000= 32%

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  • $\begingroup$ Welcome to the site. MathJaX formatting is encouraged, to improve readability, and would really help here, $\endgroup$ – The Count Feb 8 '17 at 18:47

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