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I am currently studying for the GRE exam and there are two particular questions I am unable to solved. Help with them would be much appreciated.


The first:

k = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

Which is greater, k or 2?


The second:

n = 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7

Which is greater, n or 3?


Any help with them is much appreciated.

Ilya

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  • $\begingroup$ Hint: What happens if you add $\frac1{128}$ to $k$? $\endgroup$ Jan 9, 2016 at 20:10

1 Answer 1

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Here's one way to figure out the first one. Let's consider where we get in relation to the number $2$ at each step in the sum.

The first number is $1$. That gets us halfway to $2$. The next number is $\frac 12$. This gets of half of the distance that's left. The next number is $\frac 14$. That gets of half the distance that's left again. We can see that this pattern continues (plot these points on a number line if you still don't see) so this sum will never reach $2$ after any number of finite iterations. Thus $k\lt 2$.

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Here's one way to figure out the second one

$$\color{red}{n} = (1) + \left(\frac12 + \frac13\right) + \left(\frac14 + \frac15 + \frac16 + \frac17\right) \color{red}{\lt} (1) + \left(\frac12 + \frac12\right) + \left(\frac14 + \frac14 + \frac14 + \frac14\right) = \color{red}{3}$$

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