# Does the resultant of two coprime polynomials measure something?

Let $R[X]$ be the polynomial ring over a commutative ring $R$, $f$ and $g \in R[X]$ two coprime polynomials, and $\mathrm{res}(f,g)\in R$ their resultant.

Because $f$ and $g$ are coprime, $\mathrm{res}(f,g)\neq 0$. But does this determinant, which the resultant is, measure something more?

Is it true that there are $a, b \in R[X]$ such that $af + bg = \mathrm{res}(f,g)$? If R is a Bézout domain, is $(f)+(g) = (\mathrm{res}(f,g))$?

That's true for every field. For ex. Prop. 9, p. 157. of Cox Little O'Shea (Ideals, algorithms, varieties...) old edition, or page 164, prop 5 of 2015 edition, states that; Even more, the coefficients of such a and b are pol in terms of the coefficients of f and g. I think it is true for the rings as well: Considering the field of fractions of $R$, we will be allowed to use the Cramer rule/division; At the last step we multiply everything by $Res$ and get something in $R$.