I want to derive the complex conjugate of the number $z:=\exp(a\sqrt{1-2b i})$ for $a>0$ and $b>0$. I tried to convert $z$ to standard or polar form but did not know how to deal with the square root. How should I derive the complex conjugate of $z$?

Thanks and have a nice day!

  • $\begingroup$ Consider solving the equation: $x+yi=\sqrt{1-2bi}$. $\endgroup$ – Meitar Jan 5 '16 at 15:38

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