Equivalent conditions I am looking at the following exercise: 
Show that the following are equivalent conditions on a surface patch $\sigma (u, v)$ with first fundamental form $Edu^2 + 2F dudv + Gdv^2$ :


*

*$E_v = G_u = 0$.

*$σ_{uv}$ is parallel to the standard unit normal $N$.

*The opposite sides of any quadrilateral formed by parameter curves of $\sigma$ have the same length. 


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I have done the folowing: 
$(1)\Rightarrow (2)$: 
We have that $E_v=0 \Rightarrow \sigma_{uv}\cdot \sigma_u=0$ and $G_u=0\Rightarrow \sigma_{uv}\cdot \sigma_v=0$. 
So, $\sigma_{uv}$ is perpendicular to $\sigma_u$ and $\sigma_v$. 
Since the unit normal, $N$, is perpendicular to $\sigma_u$ and $\sigma_v$, we have that $\sigma_{uv}$ is paralle to $N$. 
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$(2) \Rightarrow (1)$: 
We have that $\sigma_{uv}$ is parallel ot the unit normal $N$. 
Since $\sigma_u$ and $\sigma_v$ are tangent to the surface, so perpendicular to $N$, we have that they are perpendicular also to $\sigma_{uv}$. That means that $\sigma_{uv}\cdot \sigma_u=0$ and $\sigma_{uv}\cdot \sigma_v=0$. 
Since $E_v=2\sigma_{uv}\cdot \sigma_v$ we have that $E_v=0$ and since $G_u=2\sigma_{uv}\cdot \sigma_u$ we have that $G_u=0$. 
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Is everything correct so far? 
How can we show that $(1)-(3)$ are equivalent? Could you give me some hints? 
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$\quad$ If $\gamma$ is a curve lying in the image of a surface patch $\boldsymbol{\sigma}$, we have $$\gamma(t)=\boldsymbol{\sigma}(u(t),v(t))$$ for some smoth functions $u(t)$ and $v(t)$. Then, denoting $d/dt$ by a dot, we have $\dot\gamma=\dot{u}\boldsymbol{\sigma}_u+\dot{v}\boldsymbol{\sigma}_v$ by the chain rule, so $$\langle\dot\gamma,\dot\gamma\rangle=E\dot u^2+2F\dot u\dot v+G\dot v^2,$$ and the length of $\gamma$ is given by $$\int(E\dot u^2+2F\dot u\dot v+G\dot v^2)^{1/2}dt.\tag{6.1}$$

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EDIT1: 
$(3) \Rightarrow (1)$: 
From the IVT we have $$\left (\sqrt{E(u,\tilde{v})}\right )_v=\frac{\sqrt{E(u,v^\ast )}-\sqrt{E(u,0)}}{v^\ast}, \ \ \tilde{v}\in (0,v^\ast)$$ 
So $$\frac{E_v(u,v)}{2\sqrt{E(u,v)}} \big |_{v=\tilde{v}}=\frac{\sqrt{E(u,v^\ast )}-\sqrt{E(u,0)}}{v^\ast}$$ 
Taking the derivative we have $$\int_0^{\epsilon}\frac{E_v(u,\tilde{v})}{2\sqrt{E(u,\tilde{v})}}du=\int_0^{\epsilon}\frac{\sqrt{E(u,v^\ast )}-\sqrt{E(u,0)}}{v^\ast}du=\frac{\int_0^{\epsilon}\sqrt{E(u,v^\ast )}du-\int_0^{\epsilon}\sqrt{E(u,0)}du}{v^\ast}=0$$ 
So $$\int_0^{\epsilon}\frac{E_v(u,\tilde{v})}{2\sqrt{E(u,\tilde{v})}} du=0 \Rightarrow E_v(u,\tilde{v})=0$$ 
Is this correct?  
Or is the last implication wrong? 
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EDIT2: 
Could you give me also a hint how we could show the following? 
 
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How can we find such a reparametrization? 
 A: Let's take the $u-$parametric curve. The length is $$\int_a^b \sqrt{E(u,v)} \mathrm du$$
You need to show that this does not depend on $v$. Since $E_v = 0$ $E$ doesn't depend on $v$... Hope that you can continue from here. For the $v-$parametric lines the length is 
$$\int_a^b \sqrt{G(u,v)} \mathrm dv$$ and you repeat the same argument as above. This proves $(1) \implies (3)$.
A: First fundamental form
$$ ds^2 = E(u) du^2 + 2 F (u,v) du dv + G(v) dv^2  \tag{1} $$
and as you simplified 
$$ \Delta s = \int_a ^b \sqrt{E(u)} du = \int_c ^d \sqrt{G(v)} dv \tag {2} $$
It is a curvilinear  "parallelogram " becoming a  "rhombus", if $ a=c, b=d.$ The sum of four internal angles here is less than $2 \pi$
Taking  cross product between $ \sigma_u, \sigma_v $ having   variable direction  $ \theta$ between them, since we are allowed to use cos rule and other trig relations to differential lengths also like the following..

$$ ds_1^2 =  du^2 + 2 \cos \theta\,  du dv + dv^2  \tag{3} $$
Using the Christoffel coefficients ( several ones vanish) calculate  Gauss curvature as 
$$ K (u,v) = - \frac{\partial ^2 \theta}{\partial u  \partial v  } /\sin \theta    \tag {4} $$
which is a negative constant. This results in the Chebychev fishnet. In another form it is also stated as the Sine-Gordon Equation
$$  \frac{\partial ^2 \theta}{\partial u  \partial v  } - K (u,v) \sin \theta  =0 \tag{5} $$
The Gauss curvature can be either constant when K is negative or positive constant, or even variable as in case of a dance artist fishnet leg stockings.
