Example of a relation that is reflexive but not symmetric By definition, $R$, a relation in a set X, is reflexive if and only if $\forall x\in X$, $x\,R\,x$, and $R$ is symmetric if and only if $x\,R\,y\implies y\,R\,x$. 
I think $x\,R\,x$ can also be symmetric when I read the definition, but I also feel there's something wrong or missing in my understanding. 
Can you give an example of a relation that is reflexive but not symmetric? 
 A: A relation is symmetric if $xRy \implies yRx$ for all $x,y$. 
You always know that $xRx \implies xRx$, because it is not possible that $xRx$ is true and $xRx$ is false at the same time. This is regardless of whether $R$ is reflexive or not.
There are plenty of examples:


*

*All ordenings on sets with more than one element, in particular $\leq$ on $\mathbb N, \mathbb Z, \mathbb Q, \mathbb R$.

*$x \mid y$, that is, $x$ divides $y$, on $\mathbb N, \mathbb Z$.

A: 
Somewhere, there's a list that shows relations can be any combination of reflexive, symmetric and transitive (despite the famous false proof that symmetric + transitive -> reflexive).  – barrycarter 3 hours ago

Well, I couldn't find one to link to in a few minutes, so let me provide one here.
On the three-element set $\{a, b, c\}$, the following relations are:


*

*Transitive, symmetric: $R_0 = \emptyset$

*Transitive, not symmetric: $R_1 = \{(a,b)\}$

*Not transitive, not symmetric: $R_2 = \{(a,b), (b,c)\}$

*Not transitive, symmetric: $R_3 = \{(a,b), (b,a), (b,c), (c,b)\}$


None of the relations above are reflexive, but they can all be turned into reflexive relations, without affecting their transitivity or symmetry, by adding $R^* = \{(a,a), (b,b), (c,c)\}$ to them.
(In particular, $R_1 \cup R^* = \{(a,a), (a,b), (b,b), (c,c)\}$ is a reflexive, non-symmetric relation on the set $\{a, b, c\}$.  Of course, the restriction of this relation to the two-element subset $\{a, b\}$ yields an even simpler example.)
A: Examples are not that compelling because the conditions are so easy to meet that the general case can be constructed directly.  The ones based on $\geq$ or other (partial) orderings to create asymmetry are misleading because they are transitive, a strong extra condition that is not typical of reflexive asymmetric relations.
General construction: take any asymmetric relation and add all the $xRx$ relations needed to make it reflexive.   Any reflexive asymmetric relation is of that form. 
The picture is of any directed graph, that has a loop at every vertex.  To see examples, draw any directed graph, and put a loop at every vertex.
"Has seen" or "has telephoned the house of" are everyday examples.
A: It's important to remember quantifiers. $R$ is symmetric if and only if $x R y \Rightarrow yRx$ for all $x,y$. Certainly $x Rx \Rightarrow x R x$, but this does not mean $R$ is symmetric.
An example of a relation that is reflexive but not symmetric is $\leq$. For all $x$, $x \leq x$. However, $x \leq y $ does not imply $ y \leq x$ - for example, $1 \leq 2$, but it's not the case that $2 \leq 1$.
A: "Knows The Name of" is reflexive but not symmetric. 
Everyone knows their own name. 
$a \space R \space a$ and $b \space R  \space b$
Alan knows Bob's name: 
$a \space R \space b$
Bob does not know Alan's name- he is forgetful. 
$Not$ $b \space {R} \space a$
