# Problem regarding parabola

While studying conic sections, in the parabola portion, I read that

The sum of the ordinates of the extremities of the chords of the parabola $y^2=4.a.x$ which are parallel to each other is constant.

But I was in doubt, how is this possible, and what is this $constant$ $value$? I would be obliged if anyone can help me with this. Thanks

Consider a set of parallel chords having slope $m$. The equation of all these chords is of the form $y=mx+c$

The ordinates of the extremities of a chord will satisfy the following equation: $$y^2=4a\left({y-c\over m}\right)\implies my^2-4ay+4ac=0$$

The sum of the ordinates is just the sum of roots of that quadratic equation, which is $\dfrac{4a}{m}$

Also note that this constancy is precisely the reason that the diameters of any parabola are always parallel to its axis.

• So it is true for any number of chords I draw parallel to each other? – Aneek Dec 15 '15 at 13:59
• @Aneek yes.${}{}{}$ – G-man Dec 15 '15 at 14:00
• Well, you are brilliant, thanks! – Aneek Dec 15 '15 at 14:00