2
$\begingroup$

This question already has an answer here:

How do I prove that the determinant is the only function that has the properties of the determinant (multilinearity, being alternating, $\det(I)=1$).

In my notes we started to prove it like: suppose there is another such function (say $g$)... But from then on I can't make sense of it.

$\endgroup$

marked as duplicate by mathcounterexamples.net, Community Dec 14 '15 at 21:42

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

Browse other questions tagged or ask your own question.