I was solving some problems on CI from my textbook, there's a problem whose solution is given in my book but I can't understand it. Here is the problem -
A man borrowed a sum of money and agrees to pay it off by paying 43,200 at the end of the first year and 34,992 at the end of second year. If the reate of compound interest is 8% P.A., find the sum borrowed.
Given Solution -
For the payment of 43,200 at the end of the first year :
A = 43,200; n = 1 yr; r = 8%
$A = P(1 + R/100)^n$ => $43200 = P(1+8/100)^1$
=> $ 43200 * 100/108 = 40,000$
For the payment of 34,992 at the end of the second year :
$34,992 = P(1 + 8/100)^2$ => $P = 34,992 * (100/108)^2$ = 30,000
Sum borrowed = 40,000 + 30,000 = 70,000
I can't understand the first step. Why 43,200 is taken as amount? As far as I know the actual amount of the first year should be more than what he pays but according to the solution they are considering the amount at the end of 1 year to be exactly equal to what he repays. If he repays total amount by the first time then the principal for the second year must be zero, but according to the question that is not the case. Finally, when they add both the principals to calculate final one also seems confusing to me, probably there's something in the question I am missing. Can someone clarify the solution to me?