How do I approach a question with multiple variables and no set equations? I am very confused when it comes to related rates. I am not comprehending how I need to go about solve these questions. 
An example problem is ...
The radius of a circular oil slick expands at a rate of 6 m/min.
(a) How fast is the area of the oil slick increasing when the radius is 20 m?
(b) If the radius is 0 at time t=0, how fast is the area increasing after 3 mins?
I know that I would need to use the area of a circle formula and then differentiate implicitly but everything is still very confusing. Any guidance is appreciated.
 A: Let's look at part $(a)$:
First, write what you want as an expression:


*

*We want to know the rate at which the area is increasing, that is, ${dA\over dt}$ where $A$ represents area (measured in meters$^2$).


Second, write what you know with equations.


*

*The radius expands at a rate of $6$ m/min - that is, the ${dR\over dt}=6$, where $R$ represents the radius (measured in meters) and $t$ represents time (measured in seconds).

*The radius is $20$ meters - that is, $R=20$.

*Finally, the area and the radius of the slick are related: $A=\pi R^2$.
So to recap, we know ${dR\over dt}=6$, $R=20$, and $A=\pi R^2$; and we want to know ${dA\over dt}$. The problem is basically how to get from $A$ to $R$.
This is where the expression $A=\pi R^2$ comes in: we have ${dA\over dR}=2\pi R$. Do you see how to combine this fact with something we already know to figure out a general expression for ${dA\over dt}$? (Hint: chain rule . . .)

A: The radius of a circular oil slick expands at a rate of 6 m/min.
$$  \frac{dr}{dt} =6$$
(a) How fast is the area of the oil slick increasing when the radius is 20 m? (b) If the radius is 0 at time t=0, how fast is the area increasing after 3 mins?
$$ A = \pi r^2  $$
a) find $\frac{dA}{dt}$ when $r=20$
b) find $\frac{dA}{dt}$ when $r=6(3)=18$
