# Prove that $\sum \frac{1}{n^2} = \frac{\pi^2}{6}$ [duplicate]

In this answer two sequences are mentioned. In particular, I would like to prove that

$$\sum_{n = 1}^{+ \infty} \frac{1}{n^2} = \frac{\pi^2}{6}$$

If I knew that the sequence converges to $\frac{\pi^2}{6}$, I could use the $\epsilon$-$M$ criterion to prove the convergence to that value.

But how to prove that the above sequence converges to that value if I don't know the value itself? Is there a general way to proceed in such cases?

## marked as duplicate by Bungo, Américo Tavares calculus StackExchange.ready(function() { if (StackExchange.options.isMobile) return; $('.dupe-hammer-message-hover:not(.hover-bound)').each(function() { var$hover = $(this).addClass('hover-bound'),$msg = $hover.siblings('.dupe-hammer-message');$hover.hover( function() { $hover.showInfoMessage('', { messageElement:$msg.clone().show(), transient: false, position: { my: 'bottom left', at: 'top center', offsetTop: -7 }, dismissable: false, relativeToBody: true }); }, function() { StackExchange.helpers.removeMessages(); } ); }); }); Dec 9 '15 at 17:46

You can evaluate the summation by evaluating the double integral $\displaystyle \int_{0}^1 \int_{0}^1 \dfrac{1}{1-xy}dx dy$ (it is an exercise to prove that this indeed equals $\displaystyle \sum_{n=1}^\infty \dfrac{1}{n^2}$) and making the change of variables $x = \dfrac{u-v}{\sqrt{2}}$, $y= \dfrac{u+v}{ \sqrt{2}}$. This gives a rotation of $\dfrac{\pi}{4}$ about the origin through the angle $\dfrac{\pi}{4}$.
Although it is interesting to note that the exact value of $\displaystyle \int_{0}^1 \int_{0}^1 \int_{0}^1 \dfrac{1}{1-xyz}dx dy dz = \sum_{n = 1}^\infty \dfrac{1}{n^3}$ is unknown.