Line 1 has equation: $\dfrac{x-8}{3}=\dfrac{y+9}{-16}=\dfrac{z+1}{-2}$
Line 2 has equation: $\left(\begin{matrix}x\\y\\z \end{matrix}\right)=\left(\begin{matrix}15\\29\\5 \end{matrix}\right) + \left(\begin{matrix}3\\8\\-5 \end{matrix}\right)t$
How do you find the shortest distance between lines 1 and 2?
Also how would I find the coordinates of the points where the common perpendicular meets the line 1 and 2? Would I use cross product of direction vectors from both lines? But how would I find the coordinate that starts from?