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Let B be the set of all strings of 0’s and 1’s. A binary relation G is defined on B as follows: for all s, $t \in B$, s G t$\iff $ the number of 0’s in s is greater than the number of 0’s in t. Determine whether G is reflexive, symmetric, antisymmetric, transitive, or none of them. Justify your answer

I have no idea how to do this. Please someone help

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  • $\begingroup$ Do you know the definitions of these properties ? Do you know if the $<$ relations on the integers is reflexive ? $\endgroup$ – Mirko Nov 28 '15 at 2:17
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I'll start you off with reflexive to give you an idea. To prove $G$ is reflexive we need to show $\forall s \in B$ we have $s G s$. But since we defined our relation to be strictly greater than clearly the number of 0's in $s$ is not greater than the number of 0's in $s$.

If we think about the count of 0's in a string as a map from the alphabet 0,1 to $N$ then really this is equivalent to the $>$ operator properties.

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  • $\begingroup$ why can't I get \N to give me natural numbers? $\endgroup$ – user2879934 Nov 28 '15 at 2:20
  • $\begingroup$ Use \Bbb N or \mathbb N. $\endgroup$ – Brian M. Scott Nov 30 '15 at 14:09

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