Please, while answering/reading this question, only keep in mind my point of view only.
The question is, that how come an irrational number on a number line is a fixed point.
To make things more clear, let us consider $\pi$. We see that it is "fixed" on the number line below:
And the value of $\pi$ is incessantly:
So let us take the number $3.14$. It will evidently be fixed on the number line, because it has a finite number of digits. But when we add $1$ at the end, it shifts a little forward. Similarly, when we add $5$ in the end, it again shifts a little forward. So it goes on indefinitely, infinitely and the point keeps on shifting. So how come, an irrational number even exists on a number line. (Because infinity is not defined, it can never be achieved in reality. For example, $\lim\limits_{n\to\infty}\frac1n=0$. But this doesn't mean that the function $y=\frac1n$ will ever become $0$, it will keep on going towards, tending towards it.)
P.S.: Please don't answer as: "Don't look at the problem this way...." etc etc. Just tell me, why doesn't this point of view satisfy the existence of irrational numbers.