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I'm having trouble solving this Calculus problem and wondering if I could get some help.

"A particle is traveling around a circle whose equation is $x^2 + y^2 = 25$ in such a way that the rate of change of its $x$-coordinate with respect to time, $\frac{dx}{dt}$, $= 2$. Find the rate of change of the $y$-coordinate with respect to time, $\frac{dy}{dt}$, when the particle is at the point $(3, -4)$ on the circle."

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  • $\begingroup$ You have that $x(t)^2 + y(t)^2 =25$. What do you obtain by taking the derivate with respect to $t$? $\endgroup$ – Fabian Nov 18 '15 at 7:23
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Differentiate the given equation w.r.t to $t$ so we get $2x.dx/dt+2y.dy/dt=0$ now $x=3,y=-4 , dx/dt=2$ so substituting values we get $dy/dt=3/2$ . Hope this helps you.

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