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Consider the double sum $$\sum_{m=1}^p\sum_{n=1}^p\exp(2\pi ik(m^2-n^2)/p).$$

To simplify this, a textbook that I'm using suggests the change of variable $m=n+h$ to get $m^2-n^2=2nh+h^2$, and

$$\sum_{h=1}^p\exp(2\pi i kh^2/p)\sum_{n=1}^p\exp(4\pi ikhn/p).$$

Shouldn't the lower bound for $h$ be $1-p$ rather than $p$? Many thanks!

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The answer is right .
two $n$ in two formula are not corresponding.
It can not only change the lower bound for $h$

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  • $\begingroup$ Can you expand your answer a little bit, please? Thanks! $\endgroup$
    – EPS
    Commented Nov 18, 2015 at 18:10

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