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Basicly the title. I know it's easy but I can't figure it out. [Edit] Not a duplicate has a 2x instead of x.

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    $\begingroup$ what is $\cos 0?$ $\endgroup$ – Will Jagy Nov 15 '15 at 21:51
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    $\begingroup$ It is when $x\to 0^+$? (i.e., only by positive values?) As asked, the limit does not exist. $\endgroup$ – Clement C. Nov 15 '15 at 21:54
  • $\begingroup$ "Basically the title" is not a question. Please make your question's body self contained. If your entire question fits into the title, it is not a good question. $\endgroup$ – Asaf Karagila Nov 15 '15 at 22:39
  • $\begingroup$ If its a short question then it can fit into the title. Doesn't mean its a bad question. $\endgroup$ – Earl Smith Nov 16 '15 at 23:53
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As x approaches 0 Cos(x) approaches 1 so we can in a sense think of 1/x. As x goes to 0 from the positive side 1/x approaches infinity. But when x goes to 0 from the negative side 1/x goes instead to negative infinity. This means that the limit as x goes to 0 for Cos(x)/x is undefined as the left and right limits do not agree.

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