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Can someone please show me how to factor $6q(7(6q)^2 +5)$ to show that it is a multiple of 6? I'm working on a division algorithm problem, and I understand concepts of div alg but I really don't have much experience factoring and I can't find any good sources on learning this type of thing. Thank you in advance.

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    $\begingroup$ Isn't it a multiple of $6$ because you are multiplying it by $6$? $\endgroup$ – Brevan Ellefsen Nov 14 '15 at 21:13
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You already have shown it:

The quantity: $$6q(7(6q)^2 +5)$$

Is divisible by $6$ because of the quantity $6q$ in front of the parenthesis. The $6$ implies that the polynomial is divisible by $6$.

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  • $\begingroup$ True. Ok, thank you. For some reason I was thinking I had to isolate the 6 from the q. $\endgroup$ – JohannStrauss Nov 14 '15 at 22:25

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