m. Let $P(A) = 0.8$, $P(B) = 0.5$, and $P(A \cap B) = 0.4$.
Find $P(A^c \cap B^c)$ and $P(A^c \cup B^c)$
My answer: $P(A^c \cap B^c): 0.4$, $P(A^c \cup B^c): 0.8 + 0.5=1.3$
n. A box contains four $10$ dollar bills, six $5$ dollar bills, and two $1$ dollar bills. Two bills are taken at random from the box without replacement. What is the probability that both bills will be of the same denomination?
My answer: C$(12,2)$
o. A department has $7$ men and $5$ women on its faculty. What is the probability that women will outnumber men on a randomly selected ﬁve-member committee?
p. Of the $120$ students in a class, $30$ speak Chinese, $50$ speak Spanish, $75$ speak French, $12$ speak Spanish and Chinese, $30$ speak Spanish and French, and $15$ speak Chinese and French. Seven students speak all three languages. What is the probability that a randomly chosen student speaks none of these languages?
Any help? I want to know if I am headed in the right direction with these. How do I determine if women will outnumber men? It's a combination right?
For p, how do I do this one? Thank you