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Can someone help show me step by step how to factor:

$9x^2 - 24xy + 16y^2 - 81$

I see a difference of squares in the last two terms and am stuck at this stage (did I start wrong in doing the factoring?) :

$9x^2 - 24xy + (4y+9)(4y-9)$

Please show me the steps to get the final factored form to:

$(3x-4y+9)(3x-4y-9)$

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2 Answers 2

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HINT: $$9x^2 - 24xy + 16y^2=(3x-4y)^2$$

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HINT: $$(a-9)(a+9)$$ is the main indea

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