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This question already has an answer here:

This is the integral $$\int\frac{dx}{(x+1)(n-x)}=\int kdt$$ I just need some assistance on how to begin the left side integral and I will most likely be able to continue it from there thank you.

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marked as duplicate by Jyrki Lahtonen Nov 12 '15 at 7:01

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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All what you need to do is partial fractions for the left hand sided term then you will have two fractions and their integration will be in the form of $ln(x)$.

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  • $\begingroup$ I feel like an idiot, cant believe i did not see that.... Thank you. $\endgroup$ – Carlos V Nov 12 '15 at 4:46
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HINT : there is $(a,b)$ such as $$1/((x+1)(n-x)) = a/(x+1) +b/(n-x)$$ if $n\ne-1$

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