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Two shooters shoot a target. The known probability to hit the target of the first and second shooter are $0.70$ and $0.80$ respectively. What is the probability that the target is hit after one shot from both shooters?

I tried

$$P_1= 0.7$$

$$P_2=0.8$$

$$P=P_1+P_2-P_1P_2=0.94=94\%$$

But it seems too simple and probability is too big so i'm not sure i'm on the right way?

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    $\begingroup$ I think that you have the right answer $\endgroup$
    – stity
    Nov 10, 2015 at 17:26
  • $\begingroup$ (Assuming that the two shots are independent.) $\endgroup$
    – Brian Tung
    Nov 10, 2015 at 17:29

1 Answer 1

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Hint :

1) The probability that the target is missed by BOTH shooters is : $p=0.3\times 0.2$

2) Your answer is correct.

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