# How many boys have passed given the following conditions?

A School has $2000$ students,out of which $40$% of the students are in higher secondary.Out of the students in the higher secondary, $28$% are girls and $50$% of them passed.The overall pass percentage in the higher secondary is $40$%. How many boys passed?

My approach

School has $2000$ students,$2$/$5$ of students are in HS.$7$/$25$ of students are girls.This means,$18$/$25$ of students are boys.

And,$7$/$50$ of girls are passed.(because $1$/$2$(50%) . $7$/$25$ )

How many boys passed(=Let's say x).

Overall percentage=$40$%.

$7$/$50$ + x=$40$%.

I am not getting any link between the relations I have formed.

Can anyone guide me how to solve the problem?