At a certain university, 28% of students major in zoology. Of all the students majoring in zoology, 68% are males. It is also known that 56% of all students at the university are male. Let Z represent the event that a randomly chosen student is majoring in zoology. Let M represent the event that a randomly chosen student is male. What proportion of males at the university are majoring in zoology?
Previously solved for P(M∩Z)=0.1904 and this is correct. I've tried P(Z|M) = P(M∩Z) / P(Z), and get the answer 0.68 which is the probability that a student majoring in zoology is a male. The correct answer is 0.34, which is exactly half, but I am not sure how to get this answer.
Any help is appreciated!