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Define the following function on $\mathbb{R}$ by $d(x,y)=\dfrac{|x-y|}{\sqrt{1+x^2}\sqrt{1+y^2}}$. Prove that this is metric.

I proved the first two properties of metric. But how to prove that $d(x,y)+d(y,z)\geqslant d(x,z)$ for any $x,y,z\in \mathbb{R}$

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  • $\begingroup$ The inequality sign is incorrect. $\endgroup$ – user99914 Nov 4 '15 at 10:22
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    $\begingroup$ You've got your triangle inequality backwards, maybe that's why you're having a hard time proving it? ;) $\endgroup$ – Aaron Golden Nov 4 '15 at 10:23
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    $\begingroup$ Please sorry dear guys! :)) $\endgroup$ – ZFR Nov 4 '15 at 10:25
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    $\begingroup$ @JohnMa, I edited. Sorry for mistake $\endgroup$ – ZFR Nov 4 '15 at 10:25
  • $\begingroup$ But I still don't know how to prove it :( Can anyone show a solution? $\endgroup$ – ZFR Nov 4 '15 at 10:27
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Hint: Show that $$d(x,y)=|\sin({\rm Arctan}(x)-{\rm Arctan}(y))|$$ and then use that $|\sin(a+b)|\leq |\sin(a)|+|\sin(b)|$.

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  • $\begingroup$ One of the beautiful hints that I have ever seen. Really nice! $\endgroup$ – ZFR Nov 4 '15 at 11:09

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