I have this boolean equation:
A'.B'.C'.D' + A'.B.C'.D' + B'.C'.D + B.C'.D
Using a Karnaugh map I find I can simplify the above to:
C'.(A' + D)
I have used Wolfram Alfa website to confirm this simplification is correct.
I would like to try simplifying the original statement using Boolean algebra but get stuck along the way:
A'.B'.C'.D' + A'.B.C'.D' + B'.C'.D + B.C'.D C'.D'.(A'+ B' + A' + B) + C'.D.(B' + B) C'.D'.(A' + 1) + C'.D.1
I would be grateful if someone could point out where I have gone wrong. Thank you.