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'Given the function $g(x) = \frac{(4 - 4x^2)}{(4x^2 + 3x)}$, find the domain of g(x). From what I understand, we take the denominator and solve for x such that the equation in the denominator equals zero. The correct answers here are zero (obviously) and -0.75. I was wondering how exactly one would arrive at the number -0.75 given that the equation holds two instances of the variable x. Would anyone mind explaining the process to me? Or was this just done by trial and error? Thanks!

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$4x^2+3x=0 \iff x(4x+3)=0 \iff (x=0$ or $4x+3=0$)

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