60% of the chocolates in a box are milk chocolate, and 40% are plain chocolate. A third of the milk chocolates and a quarter of the plain chocolates contain nuts. I choose a chocolate at random from the box. Calculate the probability that I have chosen a plain chocolate that does not contain nuts.
Correct me if I am not wrong.
40% of plain chocolates = 0.40 and quarter of this are having nuts means 0.40/4= 0.1 i.e plain chocolates having no nuts =1-0.1 =0.9.
so P(P and No nuts)=P(Plain)*P(No nuts/Plain) i.e 0.4*0.9=0.36. bus this is wrong. I don't know why.
The correct answer is- 0.3