Affine hull of two points in R4 [closed]

I try to describe an affine hull of two points (1,3,2,4) and (1,4,2,3) so i try to make the linear equation which describe it .

closed as off-topic by Lord_Farin, user91500, Najib Idrissi, MathOverview, yoknapatawphaOct 10 '15 at 18:06

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• It is the straight line through these points. As you're in dimension $4$ you need $3$ linearly independent equations. – Bernard Oct 10 '15 at 10:35
• i conclude in this form which describe the above affine hull : c1[0;-1;0;1]+ [1;4;2;3] what can i do to make a linear equation from this ? – KostasC Oct 10 '15 at 16:46

You need $3$ linear equations.
Let $A=(1,3,2,4)$, $B=(1,4,2,3)$, $M=(x,y,z,t)$.
One way to go is to write the vectors $\overrightarrow{AM}= (x-1,y-3,z-2,t-4)$ and $\overrightarrow{AB}=(0,1,0,-1)$ are colinear, i.e. $$\begin{cases}x-1=0\\ \dfrac{y-3}1=\dfrac{t-4}{-1}\\z-2=0\end{cases}\quad\text{whence}\quad\begin{cases}x=1\\z=2\\y+t=7\end{cases}$$
You also can apply row reduction to the matrix: $$\begin{bmatrix}x-1&0\\y-3&1\\z-2&0\\t-4&-1\end{bmatrix}$$ to obtain the compatibility conditions for the matrix to have rank $1$. This amounts to saying the $2\times2$ minors of the matrix are equal to $0$.
Last method, if you know projective space: write the matrix: $$\begin{bmatrix}x&1&1\\y&3&4\\z&2&2\\t&4&3\\1&1&1\end{bmatrix}$$ (i.e. add a 5th coordinate equal to $1$) and write the conditions for the matrix to have rank $2$.