This question already has an answer here:

If $3/3=1, 2/2=1, 1/1=1$, then why is $0/0$ undefined? Why is it not $1$?


marked as duplicate by Winther, user147263, yoknapatawpha, Thomas, Eric Wofsey Oct 8 '15 at 18:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • 4
    $\begingroup$ If $1 = 0/0$, what are you going to do about $(0+0)/0$? $\endgroup$ – TokenToucan Oct 8 '15 at 15:44
  • $\begingroup$ There can´t be a multiplicative inverse to $0$ because $0 x=0\neq1$ $\endgroup$ – Peter Melech Oct 8 '15 at 15:45
  • 1
    $\begingroup$ Division by zero is not defined in the "real number" system. It may be defined in other number systems. So tell us what number system you want to use... $\endgroup$ – GEdgar Oct 8 '15 at 16:06

0/0 is not defined because you can find any couple of numbers a,b for which 0*a = 0*b . if defined, we would have 0/0 = a/b, and this for any possible values of a and b. Which makes way to many values for one same given number. ;-)


Not the answer you're looking for? Browse other questions tagged or ask your own question.