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Question: The wheel of a carriage is 3 feet in diameter and makes 3 revolutions per second; how fast is the train going?

I'm gonna walk myself through this and hopefully I get it right...

Well for starters, the radius of the wheel is 1.5 feet. So the circumference is $1.5\cdot2\cdot\pi=3\pi$ feet. The wheel has three revolutions per second. So it is moving at $9\pi$ feet per second right?

Can you guys help me out?

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    $\begingroup$ Assuming no slipping, yes. This is hardly trigonometry though. $\endgroup$ – Macavity Oct 8 '15 at 6:35
  • $\begingroup$ Why do you think its wrong $\endgroup$ – Archis Welankar Jan 7 '16 at 5:52

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