Approximation for $\pi$ I just stumbled upon 
$$ \pi \approx \sqrt{ \frac{9}{5} } + \frac{9}{5} = 3.141640786 $$
which is $\delta = 0.0000481330$  different from $\pi$. Although this is a rather crude approximation I wonder if it has been every used in past times (historically). Note that the above might also be related to the golden ratio $\Phi = \frac{\sqrt 5 + 1}{2} $ somehow (the $\sqrt5$ is common in both).
$$ \Phi = \frac{5}{6} \left( \sqrt{ \frac{9}{5} } + \frac{9}{5} \right) - 1 $$
or 
$$ \Phi \approx \frac{5}{6} \pi - 1 $$
I would like to know if someone (known) has used this, or something similar, in their work. Is it at all familiar to any of you?
Related Question (link).
 A: I have not seen it before.  Note that $\pi = \sqrt{a} + a$ where $a = (1+2\,\pi -\sqrt {1+4\,\pi })/2$, and what you're saying is that a  rational approximation of $a$ is 
$9/5$.  In fact, we have a continued fraction 
$$ a = 1 + \dfrac{1}{1 + \dfrac{1}{3+ \dfrac{1}{1+\dfrac{1}{1139 + \ldots}}}}$$
and $1+1/(1+1/(3+1/1)) = 9/5$.  The fact that the first omitted element, $1139$, is so large makes this a very good approximation: the error in approximating $a$ by $9/5$ is only about $3.5 \times 10^{-5}$.  Four elements later comes $7574$, so an even better approximation is $1+1/(1+1/(3+1/(1+1/(1139+1/(1+1/(15+1/1)))))) = 174530/96963$ with error about $1.4 \times 10^{-14}$.
EDIT: Perhaps even more remarkable are 
$$ \eqalign{\pi - \sqrt{1 + \dfrac{47}{35} \pi} &\approx \dfrac{6}{7}\cr
\pi - \sqrt{\dfrac{3}{5} + \dfrac{5}{2} \pi } &\approx \dfrac{216}{923}\cr}$$
corresponding to the continued fractions
$$ \eqalign{\pi - \sqrt{1 + \dfrac{47}{35} \pi} &= \dfrac{1}{1+ \dfrac{1}{6 + \dfrac{1}{126402+ \ldots}}}\cr
\pi - \sqrt{\dfrac{3}{5} + \dfrac{5}{2} \pi} &= 
\dfrac{1}{4+\dfrac{1}{3+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{19+\dfrac{1}{133286+\ldots}}}}}}}\cr}$$
A: Ramanujan found this approximation, among many others, according to Wolfram MathWorld equation 21 in linked page.  
A: This is not a complete answer, but it may be useful.
The largest root of the simple polynomial
$$x^2-3x+1$$
is 
$$\Phi^2=\frac{3+\sqrt{5}}{2}=\left(\frac{1+\sqrt{5}}{2}\right)^2=\Phi+1$$
Modifying the coefficients of the polynomial using $5$ and $6$ it becomes
$$5^2x^2-5\times6\times 3 x+6^2$$
and its largest root is this approximation to $\pi$.
$$\pi\approx \frac{6}{5}\left(\frac{3}{2}+\frac{\sqrt{5}}{2}\right)=\frac{9}{5}+\sqrt{\frac{9}{5}}$$
This procedure seems related to the one for another approximation by Ramanujan.
