Evaluate the integral by using substitution prior to integration by parts
$\int sin(lnx) dx$
$w = lnx$ .... $dw = \frac 1x$ .... $dx = e^u dw$
Integrating by parts I get
$\int sin(w) dw = sin(w)e^w - \int cos(w)e^w dw$
and I don't know how to go from there. I tried doing integration by parts again but I'm not getting anywhere. Any help is appreciated.
Edit: Integrating by parts again I get:
$e^wsin(w) - e^wcos(w) + \int e^wsin(w) dw$