Solving large multiplications in my head What would be the best approach to solve 73 x 42 in my head?
I started with 70 x 40 and then 3 x 40 and combined, but at this point I forgot what I had done and ended up getting lost and not figuring it out.
Is there a good method for solving multiplication as such in my head?
 A: Many mental calculators do mutliplications from left to right this way :
\begin{array}{r}
73\\
\times\; 42
\end{array}
\begin{array}{c l}
\text{'cross' computation} &\text{ partial result}\\
7\cdot 4=28 & 28\\ 
7\cdot 2+3\cdot 4=26 & 306\\
3\cdot 2=6 &3066
\end{array}
Other example :
\begin{array}{r}
237\\
\times\;543
\end{array}
\begin{array}{c l}
\text{'cross' computation} &\text{ partial result}\\
2\cdot 5=10 & 10\\ 
2\cdot 4+3\cdot 5=23 & 123\\
2\cdot 3+3\cdot 4 +7\cdot5=53 &1283\\
3\cdot 3+7\cdot 4=37 & 12867\\
7\cdot 3=21 & 128691\\
\end{array}
To compure the square of a number use $a^2=(a+b)(a-b)+b^2$.
For example $$78^2=80\cdot 76+2^2$$
Other methods and examples in this MSE thread.
A: I would double $73$ to get $146$, and then double it again to get $292$. I take advantage of the fact that doubling a number in your head is relatively easy since you only have to remember one number at a time. Then I would multiply that result by ten to get $2920$. This is $73\times 40$. Now I just need to add $2\times 73$, which we already calculated as $146$. Adding, we get $2920+146=3066$.
A: Your method is good.  But keep the idea that (x10 + y)(a10 + b) = xy*100 + (10a)y + (10x)b + by.  In other words there will be four things to do.
So 73*42.  1) 70*40 + 2)70*2 + 3)3*40  + 4) 2*3
which is still hard.
but you can do short cuts to simplify.  Try to get close to 50 and 25 because those factor into 100 nicely:
73*42 = 73*(50 - 8); 73*50 is 7300/2 is 3650.  Put that in the back burner.
Subract 8*72.  That's 4*144 = 2*288 = 560 + 16 = 576 
Subtract from, what was it, oh yeah, 3650.  3650 - 576 = (3650-500) - 76 = 3150 - 76 = 3100 - 26 = 3066.
There's also:
73*42 = (75 - 2)*42; 75*42 = 150*21 = 3000+ 150 = 3150.  2*42 = 84. 3150 - 84 = 3100 - 34 = 3066.
A: Another way of doing these is to change the numbers to something close but simpler to calculate, add or subtract the required amounts, and expand brackets, so in this case
$$73\times 42=(75-2)(40+2)=75\times 40-2\times 40+2\times 75-4=3000+70-4=3066$$
A: No two people's neurons are wired the same way, but if you want to multiply 2-digit numbers together in your head, you can try using the following idea.
Given
$\quad  n \,= 10 n_1 + n_0 \quad \;\;\,\text{ with } n_1, n_0 \;\,\in \{1,2,3,4,5,6,7,8,9\}$
$\quad  m = 10 m_1 + m_0 \quad \text{ with } m_1, m_0 \in \{1,2,3,4,5,6,7,8,9\}$
To multiply $n \times m$,
1). Multiply the left digits and store in your L-register,
$\tag 1  L = n_1 \times m_1$
Regard the register $L$ as having a length of $2$ (pad on the left with $0$ if necessary).
2). Multiply the right digits and store in your R-register,
$\tag 2  R = n_0 \times m_0$
Regard the register $R$ as having a length of $2$ (pad on the left with $0$ if necessary).
3.) Split the $R$ register string into your $R1$ and $F$ registers,
$\tag 3  R = R1 \, || \, F$
Release the $R$ register to 'clear' memory.
4.) Concatenate the $R_1$ digit to the right of the $L$ and store in your T-register,
$\tag 4  T = L \, || \, R_1$
Release the  $R_1$/$L$ registers to clear memory.
5). Add the '-outers' and '-inners' into your T1-register,
$\tag 5  T1 = [n_1 \times m_0] + [n_0 \times m_1]$
The number $T1$ in $\text{base-}10$ has length of at most $3$.
6). Add the two registers $T$ and $T1$ together, storing the results in 3-digit register $G$.
7). Say or think the answer,
$\tag 6 G \, || \, F$

Example 1: $73 \times 42$
Combining steps, you are saying in your head $280$, and, if nobody is looking, using your fingers to store $6$.
You add $14$ (outers) to $12$ (inners), saving $26$. 
You add $280 + 26$ giving $306$.
You say the answer, $3,066$.
Example 2: $18 \times 17$
Combining steps, you are saying in your head $015$, and, if nobody is looking, using your fingers to store $6$.
You add $7$ (outers) to $8$ (inners), saving $15$. 
You add $015 + 15$ giving $30$.
You say the answer, $306$.
Example 3: $64 \times 43$
Combining steps, you are saying in your head $241$, and, if nobody is looking, using your fingers to store $2$.
You add $18$ (outers) to $16$ (inners), saving $34$. 
You add $241 + 34$ giving $275$.
You say the answer, $2,752$.
Example 4: $97 \times 97$
Combining steps, you are saying in your head $814$, and, if nobody is looking, using your fingers to store $9$.
You add $63$ (outers) to $63$ (inners), saving $126$. 
You add $814 + 126$ giving $940$.
You say the answer, $9,409$.

The starting point for this technique can be found here:
$\quad$ What is the fastest way to multiply two digit numbers?
