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What is the value of $x$ which satisfies:

$\frac{17}{85}+\frac{19}{95}+\frac{21}{105}+\frac{23}{115}+\frac{25}{125}+\frac{x}{135}=1$

I thought $x=27$ because the numerator seems to have a pattern of adding $2$ and adding $10$ on the denominator. However, when i add it on the calculator it gives me $1.2$

Then, I just added the five terms and got $1$ so $x$ has to be $0$.

My question is Why?

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    $\begingroup$ $\frac{17}{85}=\frac{19}{95}=\cdots =\frac{25}{125}=0.2$. $\endgroup$ – user236182 Oct 4 '15 at 22:23
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Did you notice that the fractions are reducible?

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  • $\begingroup$ ah i didnt notice. $\endgroup$ – Caddy Heron Oct 4 '15 at 22:36

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