How would I find the formula that relates the height of water to the volume of water in a sphere when the water is added at 0.5cm^3/s and the sphere's radius is 1cm (or if easier, any radius, if not, stick to 1cm radius)?
How would I find the formula that relates the height of water in a sphere to the time taken when the water is added at 0.5cm^3/s and the sphere's radius is 1cm (again if easier, any radius, if not, stick to 1cm radius)?
Any one of those will do, but if you're feeling extra intrepid both would be extremely helpful, though again, I will still give best answer for just one.
Comment: I know (or at least think) it should use the chain formula thing from differentiation because it needs to relate time into the formula
V=(4/3) * pi * (h/2)^3
(I've used the sphere volume formula and replaced the r with h/2 because I want the formula to be V and h) I've put it into the formula and have
dv/dt = (dv/dh) * (dh/dt)
0.5cm^3/s = (pi * h^2)/2 * (dh/dt)
dh/dt = 1/(pi * h^2)
However I don't know what to do from there. I don't understand what that value is supposed to mean, rate at which h changes? Like, what? Any help would be appreciated, even if it doesn't go the way I just went using the chain rule.