I need some help in solving a simple equation
first example: $n/2^i = 1$ then when we solve this we get : $2^i = n$ then $i=\log_2 n$ of base 2 . Okay so I understand this.
second problem: $n/3^i = 2*i$ okay so here I am stuck since i have $n=(3^i)2*i$ then what?? can you please help me so I tried to solve this but I could not so can somebody please provide with an answer with some explanation. Thank you