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$\begingroup$

So I've encountered something I haven't seen before. Could someone tell me what the following means:

x | 5

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  • 1
    $\begingroup$ x divides 5. No remainder left $\endgroup$
    – Shailesh
    Sep 23 '15 at 13:17
  • $\begingroup$ means you can divide 5 by x without rest $\endgroup$
    – math12
    Sep 23 '15 at 13:17
  • $\begingroup$ @math12. No. It is exactly the opposite. You can divide 5 by x without a remainder. $\endgroup$
    – Shailesh
    Sep 23 '15 at 13:19
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    $\begingroup$ corrected it, thanks $\endgroup$
    – math12
    Sep 23 '15 at 13:20
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$\begingroup$

$a|b$ means that you can divide b by a without getting a nonzero remainder.

Alternatively: $b$ is a multiple of $a$.

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$\begingroup$

It means $5\div x$ is a whole number.

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$\begingroup$

The $ x | 5 $ expression would mean that any number $ x $ would be a divisor of $ 5 $ with no remainder. In other words, $ 5 $ would be evenly divisible by $ x $.

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