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A foot of the normal from the point $(4,3)$ to a circle is $(2,1)$ and a diameter of the circle has the equation $2x-y-2=0$.Then find the equation of the circle.

For the equation of the circle,we need to find the center and radius of the circle but from only the equation of the diameter,how should i find the center and the radius.Please suggest me some method.

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    $\begingroup$ Hint: if you extend the normal vector between the two given points it will pass through the center of the circle. But the center must also lie on the diameter. $\endgroup$ – lulu Sep 20 '15 at 13:24
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    $\begingroup$ @lulu,thank you,i got it. $\endgroup$ – learner_avid Sep 20 '15 at 13:43
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Write eqn. of the normal from the points given.then solve it with eqn. Of diameter you will get the centre and write the eqn. By finding the radius by distance formula bw the centre and foot of normal

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