Logic Puzzle with Eight Clues I am not sure where to start to solve this problem:


*

*Smith, Jones, and Rodriguez are the engineer, brakeman, and fireman on a train, not necessarily in that order.

*Riding on the train are three passengers with the same last names as the crewmembers, identified as passenger Smith, passenger Jones, and passenger Rodriguez.

*The brakeman lives in Denver.

*Passenger Rodriguez lives in San Francisco.

*Passenger Jones long ago forgot all the algebra that he learned in high school.

*The passenger with the same name as the brakeman lives in New York.

*The brakeman and one of the passengers, a professor of mathematical physics, attend the same health club.

*Smith beat the fireman in a game of tennis at a court near their homes.
Can you discover a theorem that tells the name of the engineer, the brakeman, and the fireman?
I am lost on where to start. Thank you
 A: This kind of problem is often solved most easily by making a table whose rows are the names and whose columns are the occupations and working through the postulates, marking the combinations $1$ (correct) and $0$ (impossible). Here's the empty table.
$$\begin{array}{r|c}
&\text{Eng.}&\text{Bman.}&\text{Fman.}\\ \hline
\text{Smith}\\ \hline
\text{Jones}\\ \hline
\text{Rodriguez}
\end{array}$$
Now number the postulates that give specific information:


*

*The brakeman lives in Denver.  

*Passenger Rodriguez lives in San Francisco.  

*Passenger Jones long ago forgot all the algebra that he learned in high school.  

*The passenger with the same name as the brakeman lives in New York.  

*The brakeman and one of the passengers, a professor of mathematical physics, attend the same health club.  

*Smith beat the fireman in a game of tennis at a court near their homes.


(6) clearly implies that Smith is not the fireman. From (2) and (4) you can infer that the brakeman is not Rodriguez: if he were, passenger Rodriguez would lie in New York, and he doesn't. At this point you can enter a couple of $0$'s in the table:
$$\begin{array}{r|c}
&\text{Eng.}&\text{Bman.}&\text{Fman.}\\ \hline
\text{Smith}&&&0\\ \hline
\text{Jones}\\ \hline
\text{Rodriguez}&&0
\end{array}$$
Now (1) and (5) imply that the mathematical physicist lives in or near Denver, so by (2) he can't be passenger Rodriguez. By (3) he also can't be passenger Jones, since he obviously hasn't forgotten high school algebra, so he must be passenger Smith. (4) tells us that the passenger with the same name as the brakeman lives in New York, so the brakeman isn't Smith, and we can enter another $0$ into our table. But Smith has to have one of the occupations, so he must be the engineer: it's the only remaining possibility. And of course nobody else can be the engineer, so we now have:
$$\begin{array}{r|c}
&\text{Eng.}&\text{Bman.}&\text{Fman.}\\ \hline
\text{Smith}&1&0&0\\ \hline
\text{Jones}&0\\ \hline
\text{Rodriguez}&0&0
\end{array}$$
And at this point it all falls into place; we must have 
$$\begin{array}{r|c}
&\text{Eng.}&\text{Bman.}&\text{Fman.}\\ \hline
\text{Smith}&1&0&0\\ \hline
\text{Jones}&0&1&0\\ \hline
\text{Rodriguez}&0&0&1
\end{array}$$
Smith is the engineer, Jones is the brakeman, and Rodriguez is the fireman.
A: *

*From (6) Smith is not Fireman

*From (3) and (5) Passenger Jones can not be the Person with brakeman because he forgot his algebra and can not be Professor.

*So passenger Jones live in New York and hence from (4) Jones is brakeman .

*So Rodriguez is fireman because smith can not be Fireman.

*And Smith is Engineer.

