I have a question that asks: Express each of the following in the form $a\sin bA$. The first part of the question asks me to do this for
$a) 6\sin A\cos A$
The answer they give is $3\sin 2A$, but I though it would be $\sin 6A$. I don't understand why I am wrong, could someone please explain?
Also the two other parts of the question was:
$b)4\sin 2A\cos 2A$
$c)\sin \frac A2 \cos \frac A2$
And I just get those ones plain wrong. Is there something I am missing about the concept?