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I have made a hollow tube (thickness $1$mm) having inner radius $89$ mm and outer radius $90$ mm (length $400$ mm, can be higher). then I made a circular (circle radius $25$ mm) cut perpendicular to tube Length. Now I want to calculate area (from extracted circle of $25$ mm radius) for a radius of $13$ mm from center. Just think in steps: 1. cut a tube from diameter. 2. take any one part of tube 3. now apply above given dimensions 4. you will get a curved Circle.

How Can I calculate radius?

How the area will be calculated as it will be half symmetry. ( I have image but it is saying i need at least 10 reputation to upload image.. i can send if some body need via email.

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  • $\begingroup$ I'm missing something. How is the thickness $1$ mm if the inner and outer radii differ by $10$ mm? It would be useful if you added a diagram... $\endgroup$ – Brian Tung Aug 25 '15 at 16:14
  • $\begingroup$ I have just noticed and edited.. Its 89mm and 90mm,,,.. thnx $\endgroup$ – Hafiz M Sajjad Aug 25 '15 at 16:14
  • $\begingroup$ You want intersection area between tube radii (90,25 mm) like what is centrally removed by drilling out, right? But I do not understand 13 mm. Can you sketch? $\endgroup$ – Narasimham Aug 25 '15 at 16:21
  • $\begingroup$ I can send Image via Email.. it is saying i need at least 10 reputation for image uploade :( $\endgroup$ – Hafiz M Sajjad Aug 25 '15 at 16:36
  • $\begingroup$ Is it so that two chord areas are excluded in the smaller circle? $\endgroup$ – Narasimham Aug 25 '15 at 16:58
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I have found the surface area (approx. $1065$ mm^2)with the help of SolidWorks but I want to know Formula to calculate analytically.

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