# Seating people around a circular table (elementary counting technique)

Eight people, including Abigail, Bethany, and Charlene, are to be seated at a circular table. Two seatings are considered distinct if, and only if, the ordering of people starting with Abigail and continuing clockwise around the table in one seating is distinct from that in the other seating. How many distinct seatings are there so that Bethany is between Abigail and Charlene?

The number of ways to seat the girls so that Abigail, Bethany, and Charlene are together is 5!. In a third of these arrangements - 40 of these arrangements - Bethany is between Abigail and Charlene.

Is this correct?

There are $\frac{3!6!}{6}=3!5!$ ways in which Abigail, Bethany and Charlene are together. I think you tried to look at the three girls as one object, but you have yet to arrange them internally. With this in mind there are actually $5!\cdot2$ ways to arrange them so that Bethany is in the middle (since there are two internal arrangements of the three persons).