Hey everyone here's the problem:
Let V be a vector space with dim(V)=n
For a particular linear transformation,f, we are given that there are two distinct eigenvalues, λ1 and λ2, with corresponding eigenspaces, E(λ1) and E(λ2).
I'm just struggling to figure out why the Jordan normal form of this linear transformation is diagonal and what it looks like. Would anyone be able to give me a reason that the Jordan normal form of this linear transformation is strictly diagonal?